# Inverse Z-Transform MCQ’s

This set of Signals & Systems Multiple Choice Questions & Answers (MCQs) focuses on “Inverse Z-Transform”.

1. Given the z-transform pair 3^{n}n^{2} u[n] ↔ X (z). The time signal corresponding to X(z^{-1}) is ___________

a) n^{2}3^{-n}u[n]

b) n^{2}3^{-n}u[-n]

c) 1n231nu[n]

d) 1n231nu[−n]

2. Given the z-transform pair 3^{n}n^{2} u[n] ↔ X (z). The time signal corresponding to dX(z)dz is ___________

a) (n-1)^{3}3^{n-1}u[n-1]

b) n^{3}3^{n}u[n-1]

c) (1-n)^{3}3^{n-1}u[n-1]

d) (n-1)^{3}3^{n-1}u[n]

3. Given the z-transform pair 3nn2 u[n] ↔ X (z). The time signal corresponding to X(2z) is ___________

a) n^{2}3^{n} u[2n]

b) (−32)nn2u[n]

c) (32)nn2u[n]

d) 6nn2u[n]

4. Given the z-transform pair 3^{n}n^{2} u[n] ↔ X (z). The time signal corresponding to z2−z−22 X(z) is ___________

a) 12(x[n+2]-x[n-2])

b) (x[n+2]-x[n-2])

c) 12(x[n-2]-x[n+2])

d) (x[n-2]-x[n+2])

5. The system described by the difference equation y(n) – 2y(n-1) + y(n-2) = X(n) – X(n-1) has y(n) = 0 and n<0. If x (n) = δ(n), then y (z) will be?

a) 2

b) 1

c) 0

d) -1

6. Given the z-transform pair

X[n]↔32z2−16, |z|<4

The z-transform of the signal y[n] = nx[n] is _________

a) 32z2(z2−16)2

b) −32z2(z2−16)2

c) 32(z2−16)2

d) −32z(z2−16)2

7. Given the z-transform pair 3^{n}n^{2} u[n] ↔ X (z). The time signal corresponding to {X(z)}^{2} is ___________

a) {x[n]}^{2}

b) x[n]*x[n]

c) x[n]*x[-n]

d) x[-n]*x[-n]

8. The value of Z−1{z2(z−a)(z−b)} is ____________

a) an+1–bn+1a+b

b) an+1–bn+1a−b

c) an+1+bn+1a−b

d) an+1+bn+1a+b

9. Given the z-transform pair

X[n]↔32z2−16, |z|<4

The z-transform of the signal y[n] = x[n+1] + x[n-1] is _________

a) (z+1)2(z+1)2−16+(z−1)2(z−1)2−16

b) z2(1+z)z2−16

c) z2(z−1)z2−16

d) (z+2)2(z+2)2−16

10. The inverse Z-transform of z/(z+1)^{2} is ______________

a) (-1)^{n+1}

b) (-1)^{n-1} n

c) (-1)^{n-1}

d) (-1)^{n+1} n

11. The value of inverse Z-transform of log(zz+1) is _______________

a) (-1)^{n}/n for n = 0; 0 otherwise

b) (-1)^{n}/n

c) 0, for n = 0; (-1)^{n}/n, otherwise

d) 0

## Average Rating